2x^2-5x+3/(10x-5)(x-1)=0

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Solution for 2x^2-5x+3/(10x-5)(x-1)=0 equation: 



2x^2-5x+3/(10x-5)(x-1)=0



Domain of the equation: (10x-5)(x-1)!=0

We move all terms containing x to the left, all other terms to the right

10x-5)(x!=1

x∈R



We multiply parentheses ..

2x^2+3/(+10x^2-10x-5x+5)-5x=0

We multiply all the terms by the denominator


2x^2*(+10x^2-10x-5x+5)-5x*(+10x^2-10x-5x+5)+3=0

We multiply parentheses

2x^2*(+10x^2-10x-5x+5)-50x^3+50x^2+25x^2-25x+3=0

We do not support expression: x^3

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